What interval is formed between A and E?

To determine the interval formed between the notes A and E, we start by counting the letter names involved: A, B, C, D, E. This gives us five letter names, which indicates that we are dealing with a fifth.

Next, we need to assess the quality of that fifth. An interval of a perfect fifth occurs when the distance between the two notes contains seven semitones. From A to E:

• The notes between A and E are A, A#, B, C, C#, D, D#, E.

• Counting the semitones from A to E:

• A to A# is 1

• A# to B is 1

• B to C is 1

• C to C# is 1

• C# to D is 1

• D to D# is 1

• D# to E is 1

Adding these together gives a total of 7 semitones. This confirms that the interval from A to E is indeed a perfect fifth.

Thus, the interval formed between A and E is classified as a perfect fifth due to the distance of seven semitones that characterizes this specific interval.